18.0126x-4.9x^2=10

Solution for 18.0126x-4.9x^2=10 equation:

18.0126x-4.9x^2=10

We move all terms to the left:

18.0126x-4.9x^2-(10)=0

a = -4.9; b = 18.0126; c = -10;
Δ = b2-4ac
Δ = 18.01262-4·(-4.9)·(-10)
Δ = 128.45375876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18.0126)-\sqrt{128.45375876}}{2*-4.9}=\frac{-18.0126-\sqrt{128.45375876}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18.0126)+\sqrt{128.45375876}}{2*-4.9}=\frac{-18.0126+\sqrt{128.45375876}}{-9.8}
$